MAYBE THEY'LL FIX IT IF Y'ALL GET GOOD GRADES

Nov 16, 2017 11:39 PM

dezzy435

Views

113400

Likes

2285

Dislikes

42

My friend is a math teacher. I thought this was hilariously and petty.

I think it would stay the same, however real life logic says it would slow down. So IDK

8 years ago | Likes 1 Dislikes 1

A=πr², dA/dt=2πr(dr/dt), when r = 6 and dr/dt=3, then dA/dt=2π(6)(3)=36π cm²/h

8 years ago | Likes 2 Dislikes 0

Basic related rates

8 years ago | Likes 1 Dislikes 0

The text being bent is distracting me from this problem

8 years ago | Likes 1 Dislikes 0

That stain is already dry around the edges, would not expand much more than it already has

8 years ago | Likes 1 Dislikes 0

0.05mm/min.

8 years ago | Likes 1 Dislikes 0

Someone try to do it without calculus.

8 years ago | Likes 1 Dislikes 0

I do not believe that is possible.

8 years ago | Likes 2 Dislikes 0

8 years ago | Likes 2 Dislikes 2

8 years ago | Likes 2 Dislikes 0

I fucking hated related rates

8 years ago | Likes 1 Dislikes 0

8 years ago | Likes 9 Dislikes 0

Area = πr^2. Derivative (rate of change) of Area = 2πr*dr. r=6,dr=3. Therefore, The answer is 2*6*3*π= 36π(cm^2/hr)

8 years ago | Likes 2 Dislikes 0

Should give the test to the art teacher.

8 years ago | Likes 1 Dislikes 0

2?

8 years ago | Likes 5 Dislikes 0

Someone didn't read the question properly. Classic.

8 years ago | Likes 1 Dislikes 0

get that access point down.

8 years ago | Likes 67 Dislikes 0

Isn't called "surfin' the internet" for nothing.

8 years ago | Likes 26 Dislikes 0

Man, the 90s were so cool.

8 years ago | Likes 2 Dislikes 0

More importantly: sit under it, wait for it to fall on you, sue school.

8 years ago | Likes 3 Dislikes 1

Happened in our school. Water pipe had broken on the top floors. One tile fell on a students desk. The school got closed, 2 years of repairs

8 years ago | Likes 1 Dislikes 0

Idk, let me look it up the answer on the internet... ahhh the wifi is down!!!

8 years ago | Likes 1 Dislikes 0

Add in that the larger the stain gets, it affects the rate of spread and you get a differential equation.

8 years ago | Likes 27 Dislikes 0

Not in this case. That is not mentioned in the given information. Stuff like this is why I hated school.

8 years ago | Likes 1 Dislikes 0

Ooh that's a slippery slope! One day it's "how big will the circle be" and the next it's:

8 years ago | Likes 7 Dislikes 0

Solve the "system of linear second order constant coefficient non-homogeneous differential equations" or SLSOCCENHDE's for short...

8 years ago | Likes 9 Dislikes 0

Ayyy, I'm learning these right now. Just finished Laplace transform.

8 years ago | Likes 2 Dislikes 0

You're ahead of us. I'm doing it too, doing systems right now. I think elliptic curves and Laplace are next. Good luck on finals!

8 years ago | Likes 2 Dislikes 0

Thanks man, you too!

8 years ago | Likes 2 Dislikes 0

Shit just got exponential

8 years ago | Likes 3 Dislikes 0

Took me a second. God damn it +1

8 years ago | Likes 2 Dislikes 0

Of course as the area increases, the evaporation will slow down the spread. What kind of maths do you need for that?

8 years ago | Likes 2 Dislikes 0

I think that just makes it a multivariate problem

8 years ago | Likes 2 Dislikes 0

This is unrealistic. The area of the stain should increase at a constant rate, thus you should calculate for the rate of increase of radius

8 years ago | Likes 4 Dislikes 0

Constant should be the amount of water /time, which would result in diminishing increase of the area

8 years ago | Likes 2 Dislikes 0

You are correct in your first statement, but I fail to see why this means diminishing increase in area? Are they not 1-1 correlated?

8 years ago | Likes 3 Dislikes 0

I was wrong, they are indeed proportional, I was thinking of the radius. However you could say that greater surface means more evaporation

8 years ago | Likes 2 Dislikes 0

“Too fast. So call the custodian already.”

8 years ago | Likes 1 Dislikes 0

The stain seems close to some electronics; maybe that will give someone an incentive to fix it.

8 years ago | Likes 1 Dislikes 0

To

8 years ago | Likes 1 Dislikes 0

Its so hilariously

8 years ago | Likes 1 Dislikes 0

Wouldn’t it just be 3cm/hr? Or does the current radius affect the speed?

8 years ago | Likes 46 Dislikes 5

[deleted]

[deleted]

8 years ago (deleted Dec 1, 2017 5:45 PM) | Likes 0 Dislikes 0

Geometrically. The variable is in the base, not the exponent.

8 years ago | Likes 6 Dislikes 1

It asks for the rate at which the area is increasing, not the radius.

8 years ago | Likes 3 Dislikes 0

dAdt = drdt 2 r pi = 3x 2 x r x 3.14 = i forgot the radius already

8 years ago | Likes 5 Dislikes 1

Related rates , man

8 years ago | Likes 1 Dislikes 0

A = pi()*r^2 so area increases exponentially faster than radius

8 years ago | Likes 1 Dislikes 0

The area should be increasing linearly, not the radius.

8 years ago | Likes 2 Dislikes 0

And that's neglecting evaporation. More area = more evaporation. Eventually they will reach equilibrium and the circle will stop growing.

8 years ago | Likes 4 Dislikes 0

3 cm/hr is dr/dt, the rate of change of the stain radius over time. To find the rate of stain area increase, we first take a derivative 1/?

8 years ago | Likes 19 Dislikes 0

with respect to time of A: A = pi * r^2, dA/dt = 2*pi*r* dr/dt. Plugging in values: 2*pi* 6*3 = 36 * pi cm^2 / sec, or about 113 cm^2/sec

8 years ago | Likes 22 Dislikes 0

Dude you went way overboard. Pi*(r+3)^2 - pi*(r)^2 is good enough for a single instant, which is what they are asking. 141.3 cm/hr

8 years ago | Likes 2 Dislikes 0

141.3 cm2/hr isn't the rate of change at the given moment, it's the linear approximation between r=6 and r=9. At r=6, dA/dt is 36pi not 45pi

6 years ago | Likes 1 Dislikes 0

It's a related rate problem. You have to take the implicit derivative of the area equation and plug in the known values.

8 years ago | Likes 55 Dislikes 0

8 years ago | Likes 6 Dislikes 0

This. Its asking for instantaneous rate of change for the area at r=6cm

8 years ago | Likes 14 Dislikes 0

See, I understand most of those words, but I still have no idea what you said. And yet I aced first year calculus...but that was forever ago

8 years ago | Likes 4 Dislikes 0

"Implicit derivative" What?

8 years ago | Likes 1 Dislikes 0

You take the derivative worth respect to time of the equation A=πr^2. Since it is with respect to time and you know the area and radius>

8 years ago | Likes 2 Dislikes 0

Change with time, the chain rule shows that you get the rates of both from the equation, A' and r'. So taking the implicit derivative gives>

8 years ago | Likes 2 Dislikes 0

dA/dr = dA/dr x dr/dt. dr/dt given at time (t) so calculate dA/dr and multiply

8 years ago | Likes 2 Dislikes 0

36π cm^2/hr

8 years ago | Likes 173 Dislikes 1

nerd

8 years ago | Likes 43 Dislikes 1

Beat me to it

8 years ago | Likes 3 Dislikes 0

Nope, don’t remember how to solve this.

8 years ago | Likes 2 Dislikes 0

You lose points if you don't show your working.

8 years ago | Likes 15 Dislikes 1

[deleted]

[deleted]

8 years ago (deleted Nov 17, 2017 5:14 AM) | Likes 0 Dislikes 0

Stuff like this is why I hated school math. You were always supposed to guess what type of laws of physics and logic the teacher ment.

8 years ago | Likes 1 Dislikes 10

I still remember how in HS our teacher asked me to teach her the equations I used at an exam. I felt dissapointed and embarrased for her.

8 years ago | Likes 1 Dislikes 2

The RADIUS is increasing at 3 cm/hr, not ares. Calculus is needed for this.

8 years ago | Likes 3 Dislikes 0

You didn't read the follow up. Teacher decides what is wrong and what is right. In my HS, you always had to assume dumb.

8 years ago | Likes 1 Dislikes 1

*area No clue why autocorrect didn’t catch that.

8 years ago | Likes 1 Dislikes 0

I thank you as a calculus teacher.

8 years ago | Likes 23 Dislikes 2

You don't. The answer is incorrect. He calculated the area, no the speed at which it increases

8 years ago | Likes 1 Dislikes 6

dr/dt = 3cm/h; A = pi*r^2; dA/dt = 2pi*r*dr = 2pi*r*3 = 6pi*r; dA/dt = 36pi @ t=6

8 years ago | Likes 1 Dislikes 0

That's a rate, and it's correct. You can see as the units are per hour

8 years ago | Likes 2 Dislikes 0

I used to have to have an umbrella over my monitor at work when was raining. Maintenance's response when it was raining, "Can't look at it

8 years ago | Likes 348 Dislikes 1

now because it's raining." Their response when it wasn't raining, "can't tell where the water was coming from because it's not raining."

8 years ago | Likes 288 Dislikes 0

We're doing our best- maintenance

8 years ago | Likes 1 Dislikes 1

My favorite one so far is "Hey, this 480V transformer is sitting in a puddle." "Eh, it's been fine for 40 years."

8 years ago | Likes 29 Dislikes 0

I shudder at the tarps and wacky sheetmetal over some MCCs and transformers I see

8 years ago | Likes 1 Dislikes 0

Definitely don't go have a look when it's raining.

8 years ago | Likes 10 Dislikes 0

Don't go have a look? I have to walk right by it to get to my desk.

8 years ago | Likes 1 Dislikes 0

Wha? It's my desk, where else am I supposed to sit? /s

8 years ago | Likes 1 Dislikes 0

Maintenance mechanic here. Gotta bug the hell out of us til we fix it just to get you to shut up.

8 years ago | Likes 161 Dislikes 4

And that's what you hire facility managers for. To constantly bitch until you fix the thing.

8 years ago | Likes 3 Dislikes 0

My dad used to work plant shutdowns. He and a small crew would work through a 5+ year backlog of maintenance requests in 3 months.

8 years ago | Likes 4 Dislikes 0

He'd get yelled at by plant personnel for making them look bad.

8 years ago | Likes 3 Dislikes 0

They eventually balanced a bucket up there & told me to let them know if it overflowed or came crashing through the ceiling tiles.

8 years ago | Likes 74 Dislikes 1

They stayed on budget I'm guessing? ????

8 years ago | Likes 33 Dislikes 0