ApexPredator22
3167
170
15
Mar 21, 2017 10:11 PM
ApexPredator22
3167
170
15
Beartrails
That's just regular satisfying if you ask me
GloBuggy53
Oh dang this is cool!
IAmLessThanThree
Thanks Dijkstra.
HPTradecraft
This wasn't satisfying at all! If anything, I'm more discontent than I've ever been.
ducklingsuck
Interesting tags you have there.
blazinglory
McDonald's all day breakfast is back?
justthemafia
Is one of those tags "aunt jemima" or am I seeing things
Justaguypassingthrough
Blood of my blood
M1nyan1e
@OP I'm kind of disappointed. I was expecting...
browsib
I was sure this was gonna end up making a swastika
joeyvelour
Expected dickbutt, or the Spanish Inquisition... strangely disappointed.
HeThrustsHisFistsAgainstthePostsandStillInsistsHeSeesYourMom
MFW watching this https://shechive.files.wordpress.com/2015/07/the-kubrick-stare-heavy-browed-look-of-insanity-11-photos-6.gif?w=500&h=188
Firecantgothroughdoorsstupiditsnotaghost
I feel like theres a math paper in here somewhere but m too bad at math to recognize or care
Iwillneverhaveacakedayifikeepdeletingmyaccount
Looks like an automatic transmission to me.
truthsmiles
Still watching... expecting dickbutt....
ApexPredator22
You will be disapointed
truthsmiles
I was. Still, +1 :-)
Hyippy
I found the swastika
teninchtaint
One of them
YoureGoingToJail
DieDeutschenKommen
hehe
reallylamelol
Worst pathfinding algorithm ever
SquarePegRoundButtHole
It's not path finding, it's flood fill.
CheeseburgertheSinister
I don't know about that. It simultaneously checks every branch in a path instead of one at a time.
simpIychaos
What I was going to say. It might be the best.
SquarePegRoundButtHole
It's a flood fill, it's not finding any path. It's basically just looking at the the last painted pixel and testing whether or not to paint
SquarePegRoundButtHole
the pixels around it.
dazedNconfuzed
At the end, I expected it to at least prune all failed paths to reveal the solution.
SquarePegRoundButtHole
Well, it's not path finding.... It's a flood fill... It doesn't know the path(s). It literally just colors the pixel next to it if different